...triangle rectangle;' " or with an Englishman who reads the same thing in his own language thus : " ' The square of the hypothenuse is equal to the sum of the squares of the two other sides of a rectangle triangle! " Thirdly, those who read in a well-known tongue,...

...the hypothenuse, and the angle at B is a right angle. Base. ART. 272. In every right angled triangle the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, as shown by the following diagram. It will be seen by examining...

...truths of exact science ; as the well-known propositions of geometry, that, in a right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the opposite sides ; that the angle at the centre of a circle is double the angle at the...

...other. The side A 0, opposite the right angle, is called the hypothenuse. It is shown by Geometry, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. It follows that the difference between the square of the hypothenuse...

...to be observed that the proposition proved in (43, Part I.), viz. that in any right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the sides bounding the right angle, is of continual application in Mensuration, and enables...

...of the hypothenuse and the other small «2 _ nZ side b is *, b is equal to — — - — For, since the square of the hypothenuse is equal to the sum of the squares of the small sides, 2sb=s2— a2 6=£2_o2 26. If the diagonal of a rectangle is c, and the...

...other. The side AC, opposite the right angle, is called the hypothenuse. It is shown by Geometry, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. It follows that the difference between the square of the hypothenuse...

...29, and raise a perpendicular BC = 17. Join AB; apply it to the scale, and it will be found 33.6. For the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular. It- is required to find the diameter of a copper, that, being...

...two sides of a right-angled triangle are given, the third may be found by means of the property that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Hence h = Ъ = —p = ^h' — b* Ex. 1. If the base is 2720, and the...

...the third. This case may be solved by means of the known property of a right angled triangle, viz. the square of the hypothenuse is equal to the sum of the squares of the two sides. It may, moreover, be solved with facility by means of the two propositions,...